In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is
- 105°
- 115°
- 125°
- 130°
Answer: Option B
I is the In-centre
So, ∠BIC = 90° + 1/2 ∠BAC
= 90° + 1/2 × 50 = 115°
I is the In-centre
So, ∠BIC = 90° + 1/2 ∠BAC
= 90° + 1/2 × 50 = 115°
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In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is
In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is
In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is
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