If tan θ + cot θ = 2, then the value of tan2θ + cot2θ is
Answer: Option A
tan θ + cot θ = 2 , On squaring both sides,
(tan θ + cot θ)2 = 4, ⇒ tan2θ + cot2θ + 2 tan θ cot θ = 4,
⇒ tan2θ + cot2θ = 4 – 2 = 2 , [tan θ . cot θ = 1]
- 2
- 1
- √2
- 0
Answer & Explanation
Answer: Option Atan θ + cot θ = 2 , On squaring both sides,
(tan θ + cot θ)2 = 4, ⇒ tan2θ + cot2θ + 2 tan θ cot θ = 4,
⇒ tan2θ + cot2θ = 4 – 2 = 2 , [tan θ . cot θ = 1]
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